在java List中進行模糊查詢的實現方法

比如我有下面這樣一個List，裡面存放的是多個Employee對象。然後我想對這個List進行按照Employee對象的名字進行模糊查詢。有什麼好的解決方案麼？

比如我輸入的查詢條件為“wang”，那麼應該返回只包含employee1的List列表。

 List list = new ArrayList();Employee employee1 = new Employee();employee1.setName("wangqiang");employee1.setAge(30);list.add(employee1);Employee employee2 = new Employee();employee2.setName("lisi");list.add(employee2);employee2.setAge(25);

方式一：

 public List search(String name,List list){ List results = new ArrayList(); Pattern pattern = Pattern.compile(name); for(int i=0; i < list.size(); i++){ Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName()); if(matcher.matches()){ results.add(list.get(i)); } } return results;}

上面那個是大小寫敏感的，如果要求大小寫不敏感，改成：

Pattern pattern = Pattern.compile(name,Pattern.CASE_INSENSITIVE);

並且上面那個是精確查詢，如果要模糊匹配，matcher.find()即可以進行模糊匹配

public List search(String name,List list){ List results = new ArrayList(); Pattern pattern = Pattern.compile(name); for(int i=0; i < list.size(); i++){ Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName()); if(matcher.find()){ results.add(list.get(i)); } } return results;}

方式二：

 public class ListLike {//定義員工類public class Employee {private String name;private int age;public int getAge() {return age;}public void setAge(int age) {this.age = age;}public String getName() {return name;}public void setName(String name) {this.name = name;}}public List list=new ArrayList();//增加員工public List addList(String name,int age){Employee employee1 = new Employee();employee1.setName(name);employee1.setAge(age);list.add(employee1);return list;}//顯示所有員工public void ShowList(){for(int i=0;i<list.size();i++){System.out.println(((Employee)(list.get(i))).getName()+" "+((Employee)(list.get(i))).getAge());}}//模糊查詢public List likeString(String likename){for(int i=0;i<list.size();i++){if(((Employee)(list.get(i))).getName().indexOf(likename)<=-1)list.remove(i);}return list;}public static void main(String arg[]){ListLike ll=new ListLike();ll.addList("wuxiao",13);ll.addList("wangwang",11);ll.addList("wanghua",12);ll.addList("xiaowang",13);ll.addList("xiaoxiao",13);ll.likeString("wang");ll.ShowList();}}

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