在java List中进行模糊查询的实现方法

比如我有下面这样一个List，里面存放的是多个Employee对象。然后我想对这个List进行按照Employee对象的名字进行模糊查询。有什么好的解决方案么？

比如我输入的查询条件为“wang”，那么应该返回只包含employee1的List列表。

List list = new ArrayList();Employee employee1 = new Employee();employee1.setName("wangqiang");employee1.setAge(30);list.add(employee1);Employee employee2 = new Employee();employee2.setName("lisi");list.add(employee2);employee2.setAge(25);

方式一：

public List search(String name,List list){  List results = new ArrayList();  Pattern pattern = Pattern.compile(name);  for(int i=0; i < list.size(); i++){   Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());   if(matcher.matches()){     results.add(list.get(i));   }  }  return results;}

上面那个是大小写敏感的，如果要求大小写不敏感，改成：

Pattern pattern = Pattern.compile(name,Pattern.CASE_INSENSITIVE);

并且上面那个是精确查询，如果要模糊匹配，matcher.find()即可以进行模糊匹配

public List search(String name,List list){  List results = new ArrayList();  Pattern pattern = Pattern.compile(name);  for(int i=0; i < list.size(); i++){   Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());   if(matcher.find()){     results.add(list.get(i));   }  }  return results;}

方式二：

public class ListLike {//定义员工类public class Employee {private String name;private int age;public int getAge() {return age;}public void setAge(int age) {this.age = age;}public String getName() {return name;}public void setName(String name) {this.name = name;}}public List list=new ArrayList();//增加员工public List addList(String name,int age){Employee employee1 = new Employee();employee1.setName(name);employee1.setAge(age);list.add(employee1);return list;}//显示所有员工public void ShowList(){for(int i=0;i<list.size();i++){System.out.println(((Employee)(list.get(i))).getName()+" "+((Employee)(list.get(i))).getAge());}}//模糊查询public List likeString(String likename){for(int i=0;i<list.size();i++){if(((Employee)(list.get(i))).getName().indexOf(likename)<=-1)list.remove(i);}return list;}public static void main(String arg[]){ListLike ll=new ListLike();ll.addList("wuxiao",13);ll.addList("wangwang",11);ll.addList("wanghua",12);ll.addList("xiaowang",13);ll.addList("xiaoxiao",13);ll.likeString("wang");ll.ShowList();}}

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