Java中使用json與前台Ajax數據交互的方法

本文主要為大家分享了Ajax獲取顯示Json數據的一種方法，供大家參考，具體內容如下
1、首先前台用Ajax，其中註意dataType一定要選擇json方式，Action成功返回給頁面的Json內容是這樣的[{"number":"V006","names":"LiLei"}],可見comment['names']對應"names":"LiLei"，comment['number']對應"number":"V006"。

 $.ajax({ type: "post", url:'apply/mystudent.action?', cache: false, dataType : "json", success: function(data){ $.each(data, function(commentIndex, comment){ alert("姓名"+ comment['names']); alert("學號"+comment['number']); }); } });

2、Ajax的URL指向在java的action中mystudent方法，返回的list其實是一個對象Student，包括了names和nunmber字段

public String mystudent() throws Exception{ List list=priceService.query();//調用接口實現類this.jsonUtil(list); return null; }

3、action頁面專門寫一個方法jsonUtil來做為json方法

// 調用json工具方法，傳入參數alist public void jsonUtil(Object accountlist) throws Exception { HttpServletResponse response = ServletActionContext.getResponse(); log.info("JSON格式：" + accountlist.toString()); String returnJson = JsonConvert.returnJson(accountlist); response.setCharacterEncoding("utf-8"); response.getWriter().println(returnJson); }

4、我用的是一種比較新的json包jackson

 import java.io.StringWriter;import org.codehaus.jackson.map.ObjectMapper;public class JsonConvert { static String jsonStr; public static String returnJson(Object object) throws Exception{ ObjectMapper objectMapper = new ObjectMapper(); StringWriter stringWriter = new StringWriter(); objectMapper.writeValue(stringWriter, object); jsonStr = stringWriter.toString(); return jsonStr; }}

以上就是本文的全部內容，希望對大家的學習有所幫助。