Java中使用json与前台Ajax数据交互的方法

本文主要为大家分享了Ajax获取显示Json数据的一种方法，供大家参考，具体内容如下
1、首先前台用Ajax，其中注意dataType一定要选择json方式，Action成功返回给页面的Json内容是这样的[{"number":"V006","names":"LiLei"}],可见comment['names']对应"names":"LiLei"，comment['number']对应"number":"V006"。

$.ajax({  type: "post",   url:'apply/mystudent.action?',  cache: false,  dataType : "json",  success: function(data){      $.each(data, function(commentIndex, comment){                     alert("姓名"+ comment['names']);                    alert("学号"+comment['number']);         });                 }                }); 

2、Ajax的URL指向在java的action中mystudent方法，返回的list其实是一个对象Student，包括了names和nunmber字段

public String mystudent() throws Exception{ List list=priceService.query();//调用接口实现类  this.jsonUtil(list);  return null; }

3、action页面专门写一个方法jsonUtil来做为json方法

// 调用json工具方法，传入参数alist public void jsonUtil(Object accountlist) throws Exception { HttpServletResponse response = ServletActionContext.getResponse(); log.info("JSON格式：" + accountlist.toString()); String returnJson = JsonConvert.returnJson(accountlist); response.setCharacterEncoding("utf-8"); response.getWriter().println(returnJson); }

4、我用的是一种比较新的json包jackson

import java.io.StringWriter;import org.codehaus.jackson.map.ObjectMapper;public class JsonConvert { static String jsonStr; public static String returnJson(Object object) throws Exception{ ObjectMapper objectMapper = new ObjectMapper(); StringWriter stringWriter = new StringWriter(); objectMapper.writeValue(stringWriter, object);  jsonStr = stringWriter.toString(); return jsonStr; }}

以上就是本文的全部内容，希望对大家的学习有所帮助。