今天遇到這種問題，單純的使用replace函數不行，他會改變原有的字串的大小寫,在網路上找到相關的程式碼，自己備份下
普通的替換函數
複製代碼代碼如下:
public function HighLight(S,F)
dim tL,tM,tR,k
tL=""
tM=""
tR=S
k=instr(1,tR,F,1)
do while k>0
tL=tL & left(tR,k-1)
tM=mid(tR,k,len(F))
tL=tL & "<span>" & tM & "</span>"
tR=right(tR,Len(tR)-len(F)-k+1)
k=instr(1,tR,F,1)
loop
HighLight=tL & tR
end function
tS="abcaBcabCaBCabcaBCa"
tF="bc"
response.Write(tS)
response.Write("<br/>")
response.Write(HighLight(tS,tF))
正規表示式
複製代碼代碼如下:
Function HighLight(S,F)
Dim regEx
Set regEx = New RegExp
regEx.IgnoreCase = True
regEx.Global = True
regEx.Pattern = "(" & F & ")"
HighLight = regEx.Replace(S,"<span>$1</span>")
End Function
Response.write HighLight("abcaBcabCaBCabcaBCa","bc")