JS method to determine whether the 360 ​​safe browser is a fast kernel

This article describes the method of JS to determine whether the 360 ​​secure browser is a fast kernel. Share it for your reference. The specific analysis is as follows:

The 360 ​​secure browser's fast kernel, the navigator.userAgent for non-360 websites is:

"Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.89 Safari/537.1", all use native Google Chrome userAgent;

And 360's own website's navigator.userAgent is

: "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.89 Safari/537.1 QIHU 360SE", which contains 360's own logo;

So it is difficult to know the 360 ​​fast kernel during our own development process;

The following method is extracted from a plug-in in a front-end blog. This method can determine the fast kernel of 360 safe browser

Copy the code as follows: function is360se(){

var where = "suffixes", value = "dll", name = "description", nameReg = /fancy/;

var mimeTypes = window.navigator.mimeTypes, i;

for (i in mimeTypes) {

if (mimeTypes[i][where] == value) {

if (nameReg.test(mimeTypes[i][name])) return false;

}

}

return true;

}

I hope this article will be helpful to everyone's JavaScript programming.