获取Display方法返回布尔值？ – JavaFX

package application; import javafx.geometry.Pos; import javafx.scene.Scene; import javafx.scene.control.Button; import javafx.scene.control.Label; import javafx.scene.layout.HBox; import javafx.scene.layout.VBox; import javafx.stage.*; /**  * An Alert Box for the GUI  * to display errors to the user.  *  */public class AlertBox{   Stage window;public boolean display(String title, String message){           boolean cancel = false;    window = new Stage();                                                               // Create the stage.            window.initModality(Modality.APPLICATION_MODAL);                                    // If window is up, make user handle it.    window.setTitle(title);    window.setMinHeight(350);    window.setMinWidth(250);    VBox root = new VBox();                 // Root layout.    Label warning = new Label(message);     // Message explaining what is wrong.    HBox buttonLayout = new HBox();         // The yes and cancel button.    Button yesButton = new Button("Yes");   // Yes button for the user.    Button noButton = new Button("No");     // No button for the user.    yesButton.setOnAction(e ->    {        cancel = false;    });    noButton.setOnAction(e ->    {        cancel = true;    });    buttonLayout.getChildren().addAll(yesButton, noButton);    root.getChildren().addAll(warning, buttonLayout);    root.setAlignment(Pos.CENTER);    Scene scene = new Scene(root);    window.setScene(scene);    window.show();}/** * Closes the window and returns whether the user said yes or no. * @param variable * @return */private boolean close(boolean variable){    window.close();    return variable;}

}

我希望我的GUI类能够准确地知道用户在AlertBox类中发生了什么.用户是否单击是或否？所以我考虑将display方法设为boolean.这就是问题所在,我的事件器表达式不能返回任何值,因为它位于void类型的回调中.然后我想,“哦,我只是让close方法返回一个布尔值”.但后来我记得原来我调用的函数是：

AlertBox warning = new AlertBox;boolean userWantsToDelete = warning.display("Warning!", "You are about to delete your account. Are you sure you would like to do this?");

它希望display方法返回一个变量,而不是close方法.我不能只是打电话给关闭,因为这不起作用.我该怎么做才能解决这个问题？非常感谢你.

Alert alert = new Alert(Alert.AlertType.CONFIRMATION);    alert.setTitle("Confirmation Dialog");    alert.setHeaderText("Warning !");    alert.setContentText("Are you sure you want to perform this action ?");    Optional result = alert.showAndWait();    if (result.get() == ButtonType.OK) {     // delete user }

result.get()返回一个布尔值.因此,您可以通过在if条件中进行比较来检查用户是否单击了ButtonType.OK或ButtonType.CANCEL.

以下是您可以了解的示例：

使用默认警报,您将获得两个按钮,一个是OK按钮,另一个是取消.但是,如果您希望自定义警报,您可以将自己的按钮类型添加到其中,如下所示：

ButtonType buttonTypeOne = new ButtonType("One");ButtonType buttonTypeTwo = new ButtonType("Two");ButtonType buttonTypeThree = new ButtonType("Three");

并将它们添加到警报中：

alert.getButtonTypes().setAll(buttonTypeOne, buttonTypeTwo, buttonTypeThree);

因此,您可以检查用户按下了哪个按钮

Optional result = alert.showAndWait();if (result.get() == buttonTypeOne){    // ... user chose "One"} else if (result.get() == buttonTypeTwo) {    // ... user chose "Two"} else{    // ... user chose "Three"}