今天遇到这种问题，单纯的使用replace函数不行，他会改变原有的字符串的大小写,在网上找到相关的代码，自己备份下
普通的替换函数
复制代码 代码如下:
public function HighLight(S,F)
dim tL,tM,tR,k
tL=""
tM=""
tR=S
k=instr(1,tR,F,1)
do while k >0
tL=tL & left(tR,k-1)
tM=mid(tR,k,len(F))
tL=tL & "< span >" & tM & "< /span >"
tR=right(tR,Len(tR)-len(F)-k+1)
k=instr(1,tR,F,1)
loop
HighLight=tL & tR
end function
tS="abcaBcabCaBCabcaBCa"
tF="bc"
response.Write(tS)
response.Write("< br/ >")
response.Write(HighLight(tS,tF))
正则表达式
复制代码 代码如下:
Function HighLight(S,F)
Dim regEx
Set regEx = New RegExp
regEx.IgnoreCase = True
regEx.Global = True
regEx.Pattern = "(" & F & ")"
HighLight = regEx.Replace(S,"< span >$1< /span >")
End Function
Response.write HighLight("abcaBcabCaBCabcaBCa","bc")